SUBNETING KELAS B CIDR 20 DAN 23

1.128.25.0.0/23 2.128.25.0.0/20 JAWABAN 1. 128.25.0.0/23 11111111.11111111.11111111.0.00000000 A. 256-2^=256-2^=256-2=254 255.255.254.0 B. 256-254=2 C. 2^=512 D. 2^-2=2^-2=512-2=510 HOST F. 2^=2^=128 BIT E. 0,2,4,6,8,10,12.....254 SUBNET= 128.25.0.0 HOST I= 128.25.0.1 HOST T= 128.25.1.254 BROADCAST= 128.25.1.255 510 TU NET= I FE FE TU DEC= 254 ITU DEC= 1 2. 128.25.0.0/20 IIIIIIII. IIIIIIII. IIII0000. 00000000 A. 256-2^=256-2^=256-16=240 255.255.240.0 B. 256-240=16 C. 2^=4096 D. 2^=2=2^-2=4096-2=4094 HOST F. 2^=2^=16 BIT E. 0,16,32,48,64.....240 SUBNET= 128.25.0.0 HOST I= 128.25.0.1 HOST T= 128.25.15.254 BROADCAST= 128.25.15.25.5 4094 HOST, F FE FE TO DEC= 254 ITU DEC= 15